(3x^2-4)-(x^3+5x^2-2x+12)=0

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Solution for (3x^2-4)-(x^3+5x^2-2x+12)=0 equation: 


Simplifying
(3x2 + -4) + -1(x3 + 5x2 + -2x + 12) = 0

Reorder the terms:
(-4 + 3x2) + -1(x3 + 5x2 + -2x + 12) = 0

Remove parenthesis around (-4 + 3x2)
-4 + 3x2 + -1(x3 + 5x2 + -2x + 12) = 0

Reorder the terms:
-4 + 3x2 + -1(12 + -2x + 5x2 + x3) = 0
-4 + 3x2 + (12 * -1 + -2x * -1 + 5x2 * -1 + x3 * -1) = 0
-4 + 3x2 + (-12 + 2x + -5x2 + -1x3) = 0

Reorder the terms:
-4 + -12 + 2x + 3x2 + -5x2 + -1x3 = 0

Combine like terms: -4 + -12 = -16
-16 + 2x + 3x2 + -5x2 + -1x3 = 0

Combine like terms: 3x2 + -5x2 = -2x2
-16 + 2x + -2x2 + -1x3 = 0

Solving
-16 + 2x + -2x2 + -1x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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